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A rental car company rents a compact car for $10 a day plus $0.50 per mile. A midsized car rents for $25 a day plus $0.30 per mile. Let C represent the total cost for a day and let M represent the number of miles

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Compact car: C = 0.60m +10
Midsized car: C = 0.40m +22

Find the number of miles at which the cost to rent either car would be the same.

Number of miles:
Cost:

User ProxyGear
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1 Answer

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Answer:

Explanation:

To find the number of miles at which the cost to rent either car would be the same, we can set the two cost equations equal to each other and solve for m:

0.60m + 10 = 0.40m + 22

0.20m = 12

m = 60

So, the number of miles at which the cost to rent either car would be the same is 60 miles.

To find the cost at this mileage, we can plug m = 60 into either of the cost equations:

For the compact car:

C = 0.60(60) + 10 = 46

For the midsized car:

C = 0.40(60) + 22 = 46

So, at 60 miles, the cost to rent either car would be $46.

User Murki
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