Answer:
To calculate the number of atoms of H and C in 0.160 mol of C6H14O, we need to first determine the number of moles of each element present in C6H14O.
The molecular formula of C6H14O shows that there are 6 carbon atoms, 14 hydrogen atoms, and 1 oxygen atom in each molecule of C6H14O.
The molar mass of C6H14O can be calculated as:
Molar mass of C6H14O = (6 × atomic mass of C) + (14 × atomic mass of H) + (1 × atomic mass of O)
= (6 × 12.01 g/mol) + (14 × 1.01 g/mol) + (1 × 16.00 g/mol)
= 86.18 g/mol
Therefore, 0.160 mol of C6H14O has a mass of:
Mass = molar mass × number of moles
= 86.18 g/mol × 0.160 mol
= 13.79 g
Now we can calculate the number of atoms of H and C in 0.160 mol of C6H14O.
Number of atoms of H:
Number of moles of H = 14 × 0.160 mol = 2.24 mol
Number of atoms of H = 2.24 mol × Avogadro's number
= 2.24 mol × 6.022 × 10^23/mol
= 1.35 × 10^24 atoms of H
Therefore, there are 1.35 × 10^24 atoms of hydrogen in 0.160 mol of C6H14O.
Number of atoms of C:
Number of moles of C = 6 × 0.160 mol = 0.96 mol
Number of atoms of C = 0.96 mol × Avogadro's number
= 0.96 mol × 6.022 × 10^23/mol
= 5.78 × 10^23 atoms of C
Therefore, there are 5.78 × 10^23 atoms of carbon in 0.160 mol of C6H14O.
Step-by-step explanation: