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What is the percent of O in

Ca(С2H302)2?
(Ca = 40.08 g/mol, C = 12.01 g/mol,
H= 1.01 g/mol, O = 16.00 g/mol)

User Zerobu
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1 Answer

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40.5%

Step-by-step explanation:

Ca×1 = 40

C×4 = 48

H×6 = 6

O×4 = 64

64÷158×100% = 40.5%

User Sashi Kant
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