Question

Can anyone help me with this? i have 6 problems like this and I don't know how to solve them.

1. y=x+4
y = 3x

2. x=-2y+1
x-y=-5

3. y=x-7
2x+y=8

4. y=3x-6
-3x+y=-6

5. x+2y=200
x=y+50

6. 4x+3y=1
x=1-y

Its Solving Using Substitution. It's also due tomorrow so please help.​

Answer 1

Sure, I can help you solve these problems using substitution. Let's start with problem 1:1. y=x+4 y=3x To solve this system of equations, we need to substitute one of the variables from one equation into the other equation. We can solve the second equation for y:y=3x Now we can substitute this expression for y into the first equation:y=x+4 3x=x+42x=4x=2 Now we can substitute this value for x into either equation to solve for y:y=x+4 y=2+4y=6 So the solution to this system of equations is x=2, y=6. You can follow the same procedure to solve the rest of the problems. 2. x=-2y+1 x-y=-53. y=x-7 2x+y=84. y=3x-6 -3x+y=-65. x+2y=200 x=y+506. 4x+3y=1 x=1-y Let me know if you need any further assistance.