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The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x- 12). What is the standard form of the equation for this line? X - 4y = 8 x -4y = 2 4x - y = 8
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The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x- 12). What

is the standard form of the equation for this line?
X - 4y = 8
x -4y = 2
4x - y = 8
• 4X -y=2

User Pozzugno
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Answer:

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Explanation:

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User DavidRguez
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