Question

Use the above equalities to calculate the following

D. How many moles of Li3P can be generated from 18.0 grams of Li2SO4?
[6 points]
E. How many grams of MgSO4 will be produced from 10.25 grams of Mg3P2?
[8 points]

Answer 1

D = 5.27 g

Step-by-step explanation:

The molar mass of Li2SO4 is 2·7 + 32 + 64 = 110

18 g Li2SO4 contains 18/110 = 0.1636 mole Li2SO4, or 0.32727 mol Li

This allows to prepare 0.1091 mol Li3P

1 mole Li3P weighs 3·7 + 31 = 52 g/mol

0.1091 mol Li3P weighs 52 g · 0.1091 = 5.27 g