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Solve the pair of simultaneous equations:(step by step, using factorization method)

y²+2y+11=x
x=5-3y​

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Answer: (-3,-2)

Explanation:

y²+2y+11 = 5-3y

y^2+2y+11-5+3y =0

y^2+5y+6=0

y^2+3y+2y+6=0

y(y+3)+2(y+3)=0

(y+3)(y+2)=0

y= -3, -2

All you do is plug in the x value to the equation

Hope it helps:)

User Jeremie Ges
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