Answer: (-3,-2)
Explanation:
y²+2y+11 = 5-3y
y^2+2y+11-5+3y =0
y^2+5y+6=0
y^2+3y+2y+6=0
y(y+3)+2(y+3)=0
(y+3)(y+2)=0
y= -3, -2
All you do is plug in the x value to the equation
Hope it helps:)
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