Answer:
3.5 x 10^3 ml
Step-by-step explanation:
We can use the ideal gas law to solve this problem:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the volume to liters and the pressure to atmospheres:
V = 3.50 x 10^-3 L
P = 3185 mmHg / 760 mmHg/atm = 4.19 atm
Next, we can solve for T:
T = PV / nR
T = (4.19 atm) (0.505 mol) (0.08206 L atm mol^-1 K^-1) / (3.50 x 10^-3 L)
T = 1074 K
Therefore, at a temperature of 1074 K (801°C or 1474°F), 0.505 mole of CO2 will occupy a volume of 3.50 x 10^3 ml at a pressure of 3185 mmHg.