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Find a equation of the line through the point(-6,-5) and (-1,1))

a. y=6/5x + 11/5
b. y=6/5x - 11/6
c. y=6/5x
or
d. y=6/5x + 11/6

User Joknawe
by
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1 Answer

2 votes

Answer:

The slope of the line passing through the points (-6,-5) and (-1,1) can be found using the formula:

slope = (y2 - y1) / (x2 - x1)

where (x1, y1) = (-6,-5) and (x2, y2) = (-1,1)

slope = (1 - (-5)) / (-1 - (-6)) = 6/5

Now, using point-slope form of the equation of a line, we get:

y - y1 = m(x - x1)

where m = 6/5 and (x1, y1) = (-6,-5)

y + 5 = 6/5(x + 6)

y + 5 = 6/5x + 6.72

y = 6/5x + 6.72 - 5

y = 6/5x + 1.72

Therefore, the equation of the line passing through the points (-6,-5) and (-1,1) is:

y = 6/5x + 1.72

Option (c) y=6/5x is not the correct equation of the line. The correct answer is (d) y=6/5x + 11/6.

User Melkor
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7.9k points