Question

the front of a tent has the shape of an isosceles triangle with equal sides of 163 cm long. the measure of the angle at the peak of the tent is 103 degrees. determine the height of the tent to the nearest centimetre. ​

Answer 1

To find the height of the tent, we need to use trigonometry. Let's draw a diagram to help visualize the problem

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h / | \ h

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b 81.5 b

We can see that the height of the tent (h) forms one leg of a right triangle, with the base (b) being half of one of the equal sides of the isosceles triangle. We can use the angle at the peak of the tent (103 degrees) to find the height using the tangent function:

tan(103) = h/b

To find b, we can use the fact that the equal sides of the isosceles triangle are 163 cm long, so b = 163/2 = 81.5 cm.

Now we can plug in b and the angle measure into the tangent equation and solve for h:

tan(103) = h/81.5

h = 81.5 * tan(103)

h ≈ 370.5 cm

Therefore, the height of the tent is approximately 370.5 cm or 371 cm to the nearest centimeter.