Question

What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of

gravity only (9.8m/s²)?

Answer 1

9800N

Step-by-step explanation:

Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8ms2 = 9800N