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What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of gravity only (9.8m/s²)?
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What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of

gravity only (9.8m/s²)?

User Gep
by
8.0k points

1 Answer

2 votes

Answer:

9800N

Step-by-step explanation:

Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8ms2 = 9800N

User Misterzik
by
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