Answer:
The total number of fruits Halston can choose is 3 + 4 + 2 = 9.
The number of ways she can choose two fruits without restrictions is 9C2 = (98)/(21) = 36.
The number of ways she can choose two fruits where both are bananas is 2C2 = 1.
Therefore, the number of ways she can choose two fruits that are not bananas is 36 - 1 = 35.
So, the probability that Halston chooses two fruits that are not bananas is:
35/36
Therefore, the probability that Halston chooses two fruits that are not bananas is 35/36.