Answer: Therefore, 70.7 mL of 9.89 M nitric acid solution should be used to prepare 3.50 L of 0.200 M HNO3.
Step-by-step explanation:
To prepare 3.50 L of 0.200 M HNO3, we need to calculate the amount of HNO3 required and then determine the volume of 9.89 M nitric acid solution needed to prepare this amount of HNO3.
The amount of HNO3 required can be calculated using the formula:
amount of HNO3 (in moles) = volume of solution (in liters) x concentration of HNO3 (in moles per liter)
Substituting the given values:
amount of HNO3 = 3.50 L x 0.200 mol/L = 0.700 mol
Now, we can use the amount of HNO3 and the concentration of the nitric acid solution to calculate the volume of the nitric acid solution needed:
volume of nitric acid solution = amount of HNO3 (in moles) / concentration of nitric acid solution (in moles per liter)
Substituting the given values:
volume of nitric acid solution = 0.700 mol / 9.89 mol/L = 0.0707 L
Finally, we can convert the volume to milliliters:
volume of nitric acid solution = 0.0707 L x 1000 mL/L = 70.7 mL
Therefore, 70.7 mL of 9.89 M nitric acid solution should be used to prepare 3.50 L of 0.200 M HNO3.
Regenerate response