Question

In simplest radical form, what are the solutions to the quadratic equation 0 = –3^2 – 4x + 4

Answer 1

Answer: x = -2,
`(2 )/(3)`

Explanation:

Given:

0 = –3x² – 4x + 4

The quadratic formula:

`\displaystyle x=(-b\pm√(b^2-4ac) )/(2a)`

Substitute known values:

* a = -3, b = -4, c = 4

`\displaystyle x=(-(-4)\pm√((-4)^2-4(-3)(4)) )/(2(-3))`

Simplify with multiplication:

`\displaystyle x=(4\pm√(16+48) )/(-6)`

Simplify:

`\displaystyle x=(4\pm√(64) )/(-6)`

`\displaystyle x=(4+8 )/(-6)`,
`\displaystyle x=(4-8 )/(-6)`

`\displaystyle x=(12 )/(-6)`,
`\displaystyle x=(-4 )/(-6)`