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The school production of 'Our Town' was a big success. For opening night, 438 tickets were sold. Students paid $4.00 each, while non-students paid $6.00 each. If a total of $2146.00 was collected, how many students and how many non-students attended?​

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Answer:

Let's use the variables "s" to represent the number of students attending and "n" to represent the number of non-students attending.

From the problem statement, we know that:

s + n = 438 (Equation 1)

And we also know that the total amount collected is $2146.00, so:

4s + 6n = 2146 (Equation 2)

We can solve for one of the variables in terms of the other by rearranging Equation 1:

s = 438 - n

Substituting this into Equation 2, we get:

4(438 - n) + 6n = 2146

Expanding and simplifying:

1752 - 4n + 6n = 2146

2n = 394

n = 197

So there were 197 non-students attending. Substituting this value back into Equation 1, we get:

s + 197 = 438

s = 241

So there were 241 students attending.

Therefore, 241 students and 197 non-students attended the school production of 'Our Town' on opening night.

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