Question

Find the equation of a line parallel to

y-3 = - 3/2x that passes through the

point (4, -5).

a. 3x+2y=2

b. y=3/2x+1

c. y=-2/3x-3

d. -2x+3y=-23

Answer 1

mine is correct

Given

a line is giving as

y-3=3/2x

and the point is(4-5)

To Find

the equation of the line parallel line (I) and passing through the point (4-5)

Explanation

let. be the equation of the required line be

y=mx+c

since it is parallel to equation o

m=3/2

hence the equation of the required line is

y= -3/2X+X

since it passes through the point (4-5)

-5=-3/2×4+c

=C=1

thus the equation of the required line is

y= -3/2x+1

=y+3/2x=1

=2y+3x=2

=3x+2y=2

therefore the correct option is (a)

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Answer 2

b. y = -3/2x + 1

Explanation:

A parallel line has the same slope as the line in question. The only difference is the y-intercept, which you calculate by plugging in the given point.

The original line: y = -3/2x + 3

The parallel line: -5 = -3/2(4) + y-intercept

-5 = -6 + y-intercept. So, y-intercept = 1

This means that the parallel line is b, y = -3/2x + 1.