Answer: H = 46.3
Step-by-step explanation: We know that H varies jointly as R and the square of C. This can be written as:
H = kRC^2
where k is the constant of variation.
We are given that C = 10 and H = 207.1 when R = 8. We can use this information to find k:
207.1 = k(8)(10)^2 k = 0.259
Now we can use this value of k to find H when C = 4 and R = 6:
H = (0.259)(6)(4)^2 H = 46.3 (rounded to the nearest tenth)
Therefore, when C = 4 and R = 6, H is approximately equal to 46.3.
Hope this helps, and have a great day!