Final answer:
Using the Central Limit Theorem, the z-scores for the sample mean values $155 and $160 are calculated, and the corresponding probabilities are found using a normal distribution table or calculator. The probability that the sample mean is between these two values is approximately 0.073.
Step-by-step explanation:
To find the probability that the sample mean of the closing stock prices is between $155 and $160, we can use the Central Limit Theorem (CLT) because the sample size n=52 is sufficiently large. According to the CLT, the distribution of the sample mean will be approximately normally distributed with a mean (μ) equal to the population mean and a standard deviation (σ/√n) equal to the population standard deviation divided by the square root of the sample size.
The population mean (μ) is $150 and the population standard deviation (σ) is $25. The sample size (n) is 52. Using these values, the standard deviation of the sample mean is $σ/√n = $25/√52 ≈ $3.47.
Next, we calculate the z-scores for the sample mean values $155 and $160:
For $155: z = ($155 - $150) / $3.47 ≈ 1.441
For $160: z = ($160 - $150) / $3.47 ≈ 2.882
Using a standard normal distribution table or a calculator, we find the probabilities corresponding to these z-scores:
Probability for z=1.441 is approximately 0.925
Probability for z=2.882 is approximately 0.998
The probability that the sample mean is between $155 and $160 is the difference between these two probabilities:
P($155 < X < $160) = P(z<2.882) - P(z<1.441) ≈ 0.998 - 0.925 = 0.073
Therefore, the probability is 0.073, or to three decimal places, 0.073.