Question

What is the solution to x2 + 4x > 12?

x < –6 or x > 2
–6 < x < 2
x < –2 or x > 6
–2 < x < 6

Answer 1

Answer: The solution to x2 + 4x > 12 is x < –2 or x > 2.

Here's how to solve it:

x2 + 4x > 12

x2 + 4x - 12 > 0 (subtracting 12 from both sides)

(x + 6)(x - 2) > 0 (factoring the left side)

Now, we can use the zero product property and set each factor equal to 0:

x + 6 > 0 or x - 2 > 0

x > -6 or x > 2

The solution is the union of the two intervals, which is x < –2 or x > 2.

Explanation: