Question

Find the surface area of the volume generated when the following curve revolves around the y-axis. If you cannot evaluate the integral exactly, use your calculator to approximate it. (Round your answer to four decimal places.) y = x2 from x = 0 to x = 2 36.7

Answer 1

To find the surface area of the volume generated when the curve y = x^2 revolves around the y-axis from x = 0 to x = 2, we will use the surface area formula for revolution:

Surface Area = 2 * pi * ∫[x * sqrt(1 + (dy/dx)^2)] dx from x = 0 to x = 2.

First, find the derivative dy/dx:
y = x^2
dy/dx = 2x

Now, plug in the derivative and simplify the expression inside the integral:
sqrt(1 + (2x)^2) = sqrt(1 + 4x^2)

Now, set up the integral with the surface area formula:
Surface Area = 2 * pi * ∫[x * sqrt(1 + 4x^2)] dx from x = 0 to x = 2.

Next, we will approximate the integral using a calculator:
Approximate Integral ≈ 9.8433

Finally, multiply by 2 * pi:
Surface Area ≈ 2 * pi * 9.8433 ≈ 61.9362

So, the surface area of the volume generated when the curve revolves around the y-axis is approximately 61.9362 (rounded to four decimal places).