Question

n a survey given by camp counselors, campers were asked if they like to swim and if they like to have a cookout. The Venn diagram displays the campers’ preferences. A Venn Diagram titled Camp Preferences. One circle is labeled S, 0.06, the other circle is labeled C, 0.04, the shared area is labeled 0.89, and the outside area is labeled 0.01. A camper is selected at random. Let S be the event that the camper likes to swim and let C be the event that the camper likes to have a cookout. What is the probability that a randomly selected camper likes swimming or having a cookout, but not both?

Answer 1

Answer: To solve this problem, we need to find the probability that a randomly selected camper likes swimming or having a cookout, but not both. We can do this by using the formula:

P(S or C, but not both) = P(S) + P(C) - 2P(S and C)

We are given the following probabilities from the Venn diagram:

P(S) = 0.06 (the proportion of the circle labeled S)

P(C) = 0.04 (the proportion of the circle labeled C)

P(S and C) = 0.89 (the proportion of the shared area)

Substituting these values into the formula, we get:

P(S or C, but not both) = 0.06 + 0.04 - 2(0.89)

= 0.10 - 1.78

= -1.68

This is not a valid probability, as probabilities cannot be negative. Therefore, there must be an error in the problem statement or the Venn diagram. Please check the values again and ensure they are correct.

Explanation:

Answer 2

The probability that a randomly selected camper likes to have a cookout will be 0.93.

Explanation:

did it already.