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In △ABC, AB=8 cm, AC=13 cm, and m∠A=48°.
What is the area of △ABC?

Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth.

User Elo
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2 Answers

2 votes

Answer:

Explanation:

You can use the formula for the area of a triangle when you know two sides and the included angle: Area = (1/2)ab * sin©, where a and b are the lengths of the two sides and C is the measure of the included angle.

In this case, you know that AB = 8 cm, AC = 13 cm, and m∠A = 48°. So you can plug these values into the formula to find the area of △ABC:

Area = (1/2)(8 cm)(13 cm) * sin(48°) Area ≈ 41.57 cm²

So the area of △ABC is approximately 41.57 cm², rounded to the nearest hundredth.

Received message. Sure! You can use the formula for the area of a triangle when you know two sides and the included angle: Area = (1/2)ab * sin(C), where a and b are the lengths of the two sides and C is the measure of the included angle. In this case, you know that AB = 8 cm, AC = 13 cm, and m∠A = 48°. So you can plug these values into the formula to find the area of △ABC: Area = (1/2)(8 cm)(13 cm) * sin(48°) Area ≈ 41.57 cm² So the area of △ABC is approximately 41.57 cm², rounded to the nearest hundredth.

User Alex Yakunin
by
7.8k points
4 votes

Answer:

30.31
cm^(2)

Explanation:

User Mike Dewar
by
8.8k points