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What is the wavelength of light that shines on two slits that are 6 X 10^-5 meters apart and that angle between m=0 and m=1 interference lines is 10 degrees

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Answer:

Step-by-step explanation:

We can use the equation for the wavelength of light that passes through a double-slit interference pattern

λ = (d * sinθ) / m

where λ is the wavelength of light

d is the distance between the two slits

θ is the angle between the m=0 and m=1 interference lines

m is the order of the interference line.

Given that

d = 6 X 10^-5 meters

θ = 10 degrees

Interference between the m=0 and m=1 interference lines, so m = 1

Converting θ to radians:

θ = 10 degrees = 0.174533 radians

Put the values in given equation

λ = (6 X 10^-5 meters * sin(0.174533 radians)) / 1

λ ≈ 6.89 X 10^-7 meters

Therefore, the wavelength of light that shines on two slits that are 6 X 10^-5 meters apart and that angle between m=0 and m=1 interference lines is 10 degrees is approximately 6.89 X 10^-7 meters.

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