Question

Question 7 of 10

How much energy is required to raise the temperature of 3 kg of iron from 20
C to 25°C? Use the table below and this equation: Q = mc&T.
Substance Specific Heat Capacity (J/(g-*C))
Liquid water
4.186
Ice
Air
Aluminum
Soil
Granite
Iron
Copper
Silver
Lead
OA. 1350 J
B. 6750 J
C. 13.50 J
D. 2.25 J
2.11
1.00
0.897
0.80
0.790
0.450
0.385
0.233
0.129

Answer 1

Answer: 6750 J

Step-by-step explanation:

The solution ends up being a rather basic plug and chug formula.

m = mass of substance in question - measured in grams

so for this problem that is 3 kg iron, which is (3000g)

c = is the specific heat capacity for the substance. This is the maximum amount of thermal energy (Ek/ Etc) you can add to the substance before the intra molecular forces weaken (either for a solid or liquid) sufficiently for phase change energy (Eph) to be added and the substance changes states.

for this problem, the substance in question is iron - which has a specific heat capacity of (.450 j/g-*c) . j/g-*c simply means the amount of Jules required to raise one gram of said substance one degree celcius.

(change in)T = just the change in temperature provided by the parameters of the problem

for this problem it is simply (25 *C - 20*C), which equals (5*C)

to solve you just multiply the parts together ----

(3000g)(.450 j/g-*c)(5*C) = 6750j