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Carl has a piece of toast that has jelly on one side, and he dropped it twice. Both times, it landed with the jelly side up. If he drops it two more times, what is the probability that it will have landed jelly side up a total of three times? (1 point)

Group of answer choices

one over four

one over three

one over two

two over three

User EricTalv
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8.0k points

2 Answers

4 votes

Answer:

The probability of the toast landing jelly side up in each drop is 1/2, since there are two equally likely outcomes: jelly side up or jelly side down. The probability of it landing jelly side up three times out of four drops can be calculated as follows: P(jelly side up on first drop) x P(jelly side up on second drop) x P(jelly side up on third drop) x P(jelly side down on fourth drop) = 1/2 x 1/2 x 1/2 x 1/2 = 1/16 However, since the toast has already landed jelly side up twice in a row, we can simply consider the remaining two drops. The probability of it landing jelly side up in one of these two drops, given that it has already landed jelly side up twice, is still 1/2. So, the probability of the toast landing jelly side up a total of three times is: P(jelly side up on first two drops) x P(jelly side up on either of the remaining two drops) = 1/2 x 1/2 = 1/4 Therefore, the answer is one over four.

User Maertz
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8.1k points
5 votes
One over four
Is the correct
User Amadeus Hein
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7.9k points