Question

Write the cubic polynomial function f(x)in expanded form with zeros −6,−5,and −1,given that f(0)=60.

Answer 1

Explanation:

f(x) = 2 (x+6)(x+5)(x+1) .

Added multiplier 2 because 6×5×1 = 30. But it's given that f(0) = 60.

f(x) = 2x³ + 24 x² +82 x 60

Answer 2

To write the cubic polynomial function f(x) in expanded form with zeros −6, −5, and −1, we can use the factored form of a cubic polynomial. The factors of this polynomial are (x + 6), (x + 5), and (x + 1) . Therefore, the cubic polynomial function f(x) in factored form is f(x) = a(x + 6)(x + 5)(x + 1). We also know that f(0) = 60. Substituting x = 0 in the equation gives us: f(0) = a(6)(5)(1) = 30a. Therefore, a = 2. Substituting this value of a in the factored form of the polynomial gives us: f(x) = 2(x + 6)(x + 5)(x + 1). Expanding this expression gives us the cubic polynomial function f(x) in expanded form with zeros −6,−5,and −1 as: f(x) = 2x^3+14x^2+11x-60