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Quadratic function in standard form having zeros of 3 and 1/2

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The standard form of a quadratic function is:

`f(x) = ax^2 + bx + c`

If the zeros of the function are 3 and 1/2, then the factors of the function are:

`(x - 3)` and `(x - 1/2)`

To find the quadratic function using these factors, you can first multiply them together:

`(x - 3)(x - 1/2) = x^2 - 7/2x + 3/2`

Now we have:

`f(x) = x^2 - 7/2x + 3/2`

This is the quadratic function in standard form that has zeros of 3 and 1/2.

User Sakinah
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