Question

If the boiling point elevation of an aqueous solution containing a non-

volatile electrolyte is 1.02° C, what is the molality of the solution?

Answer 1

Molality of the solution is 1.9922 m.

Step-by-step explanation:

The boiling point elevation (ΔTb) of a solution can be calculated using the following formula:

ΔTb = Kb x molality

∴ Kb is the ebullioscopic constant of the solvent (water in this case) and molality is the molality of the solution.

For water, Kb = 0.512 °C/m.

From the problem statement, ΔTb = 1.02 °C. Plugging these values into the equation above, we get:

1.02 °C = 0.512 °C/m x molality

Solving for molality, we get:

molality = 1.02 °C / (0.512 °C/m) = 1.9922 m

Therefore, the molality of the solution is 1.9922 m.