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Make up an equation for a Quadratic function whose graph satisfies the given condition. Use

whatever form is most convenient.
Has a y-intercept at (0,8)

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Answer: The equation of the quadratic function is y = ax^2 + 8, where a is any non-zero constant.

Explanation: The general form of a quadratic function is y = ax^2 + bx + c, where a, b, and c are constants. To find the equation of a quadratic function with a y-intercept at (0,8), we substitute x = 0 and y = 8 into the general equation to obtain:

8 = a(0)^2 + b(0) + c 8 = c

Therefore, c = 8, and the quadratic function is y = ax^2 + bx + 8.

Since we don't have any other condition to determine the values of a and b, any non-zero value of a can be chosen to satisfy the given condition. If a positive value is chosen for a, the graph of the function will open upwards, while choosing a negative value will make it open downwards. The value of b will alter the position of the vertex of the graph.

Hope this helps, and have great day!

User Paras Chauhan
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