m(x)=2(x+6)(x+2) is the best form to reveal the zeros.
The second choice is an un-factored quadratic, and the third choice is a quadratic in vertex form, which requires adding 8 to both sides, then dividing by 2, and taking the square root. The first choice easily reveals the roots when y=0.
Let’s find the roots:
(0)=2(x+6)(x+2)
We will distribute the 2 back into the first binomial for simplicity:
0=(2x+12)(x+2)
By the zero product property, if a•b=0, then a=0 or b=0:
2x+12=0
Solve for x:
2x=-12
x=-6
2nd binomial
x+2=0
Solve for x:
x=-2
So, the roots are x=-6, -2