Question

I really need help, my test is tomorrow and it's crucial to my grade. im offering 30 points please

Answer 1

Put them in order by the amount of Y
6y^2 has 2 Y’s and the most. Then 19y ( only has 1) and the one with 0 y’s goes last. I want you to do well on the test so I will not
Give you all the answers but I hope that helps. I haven’t don’t this in awhile is the ones with GCF I can maybe help
More in the comments?

Answer 2

9, 10, 3y, 5, 3y, 5

Explanation:

First look at the second row

_(2y+3)+_(2y+3)

We know that if we multiply the first blank time 2y is should equal 6y^2, so the answer for the first one is 3y. The third blank times 3 should be 15, so the answer for the third one is 5. Therefore, 3y(2y+3)+5(2y+3).

Now if we distribute, we get the answer for the first part: 6y^2+9y+10y+15.

In the second line we got, 3y(2y+3)+5(2y+3), we can factor out the 2y+3 and end up with (2y+3)(2y+5).