Question

W Z

X
Given: XZ I WY, AWXZ and AYXZ are right triangles
WZ; y cos (W) = WZ
z; XZsin (W) = y
Step 1: cos (W) =
Step 2: sin (W) =
Step 3: ZY=z-y cos (W)
Step 4: w²= (z-y cos (W))² + XZ²
Which step contains the first error in calculation?
OA. Step 1-the cosine ratio was applied incorrectly
OB. Step 2-the sine ratio was applied incorrectly
OC. Step 3-the incorrect value was subtracted
OD.
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Step 4- the area formula should have been used instead.

Answer 1

ok, so

Explanation:

We know that WZ and ZY are perpendicular, so XY and ZY has to be also perpendicular.

We also know that WY and XZ are similar sides, so:

Since 2 sides are congruent, they share a side and they are right triangles, by Pythagoras's theorem the third sides are also congruent. Both triangles share the ZY side, both have a 90° angle, and WY=XZ.

Answer 2

Explanation:

Step 4 contains the first error in calculation.

The equation used in Step 4 is the Pythagorean theorem, which relates the sides of a right triangle. However, the triangle used in this step (ZYX) is not necessarily a right triangle, so the Pythagorean theorem cannot be applied.

Instead, the correct formula to find the length of WZ would be the law of cosines:

WZ² = XZ² + ZY² - 2(XZ)(ZY)cos(W)

Therefore, the correct Step 4 would be:

Step 4: WZ² = XZ² + ZY² - 2(XZ)(ZY)cos(W)