Answer:
The volume of the 0.76 M NaCl solution containing 0.35 g of NaCl is approximately 7.89 mL.
Step-by-step explanation:
To solve this problem, we need to use the relationship between the amount of solute (in moles), concentration (in molarity), and volume (in liters):
amount of solute (in moles) = concentration (in M) x volume (in L)
First, let's calculate the amount of NaCl in moles using the given mass and molarity:
moles of NaCl = mass of NaCl / molar mass of NaCl
moles of NaCl = 0.35 g / 58.44 g/mol (molar mass of NaCl)
moles of NaCl = 0.005992 mol
Next, we can use the above equation to solve for the volume of the solution:
0.005992 mol = 0.76 M x volume (in L)
volume (in L) = 0.005992 mol / 0.76 M
volume (in L) = 0.00789 L or 7.89 mL (rounded to three significant figures)
Therefore, the volume of the 0.76 M NaCl solution containing 0.35 g of NaCl is approximately 7.89 mL.