Answer:
In the equation w = 200 - 10t, the variable "w" represents the number of fish caught at a given time, and the variable "t" represents the time elapsed (in hours) since the fishing activity began.
The equation is a linear equation in slope-intercept form, where the coefficient of "t" (-10) represents the rate of change of the number of fish caught per unit of time (i.e., per hour), and the intercept (200) represents the initial number of fish that were available for catching at the beginning of the fishing activity.
Or
o solve the equation w = 200 - 10t for either variable w or t, we can use algebraic manipulation as follows:
Solving for w:
Subtract 200 from both sides of the equation:
w - 200 = -10t
Add 200 to both sides of the equation:
w = -10t + 200
Therefore, the number of fish caught w can be expressed as a function of time t by the equation w = -10t + 200.
Solving for t:
Subtract w from both sides of the equation:
w - 200 = -10t
Divide both sides of the equation by -10 (or multiply both sides by -1/10):
(w - 200)/(-10) = t
Therefore, the time elapsed t can be expressed as a function of the number of fish caught w by the equation t = (200 - w)/10.
These two equations are equivalent to the original equation w = 200 - 10t and can be used to calculate either the number of fish caught or the time elapsed for a given value of the other variable.
Explanation: