Question

PLEASE HELP FOR A DECENT AMOUNT OF POINTS At an animal shelter the number of dog adoptions one weekend was 10 less than 3 times the number of cat adoptions. the number of cat adoptions plus twice the number of dog adoptions was 8 . how many cats and how many dogs were adopted that weekend

SOLVE USING ELIMINATION
PLEASE SHOW ALL STEPS

Answer 1

4 cats and 2 dogs were adopted that weekend.

Explanation:

Let's use elimination to solve this system of equations:

d = 3c - 10 (Equation 1)

c + 2d = 8 (Equation 2)

First, we can rearrange Equation 1 to isolate d:

d = 3c - 10

Next, we can substitute this expression for d into Equation 2 and solve for c:

c + 2(3c - 10) = 8

c + 6c - 20 = 8

7c = 28

c = 4

Now that we have found the value of c, we can substitute it back into Equation 1 to find d:

d = 3c - 10

d = 3(4) - 10

d = 2

Therefore, 4 cats and 2 dogs were adopted that weekend.