Question

HURRY PLS I DONT HAVE ANY TIME

A standard deck of cards has 13 cards that are clubs and 13 cards that are hearts. A card is chosen from a standard deck of cards. It is then replaced, and a second card is chosen from the deck. What is P(at least one card is a club)? 1 over 26 one fourth one half three fourths

Answer 1

Answer:The probability of choosing a card that is not a club on the first draw is 26/52, since there are 26 cards that are not clubs in the deck. The probability of choosing a card that is not a club on the second draw, assuming that the first card was not a club and was replaced, is also 26/52.

Explanation:

Therefore, the probability of choosing at least one club in the two draws is:

1 - (26/52 x 26/52) = 1 - (676/2704) = 1 - 0.25 = 0.75

So the answer is three fourths (3/4).