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you have 40.0 ml of 0.100 m phosphoric acid that you titrate with 0.100 m naoh. what will be the major phosphate species present after the addition of 40.0 ml of naoh?

User Jay Zhao
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2 Answers

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Answer:

The addition of 40.0 mL of 0.100 M NaOH to 40.0 mL of 0.100 M phosphoric acid will result in the major phosphate species being HPO4^2-. This is because the first two hydrogen ions (H+) in phosphoric acid will be neutralized by the NaOH, leaving behind one hydrogen ion and producing HPO4^2-.

Step-by-step explanation:

User Pptt
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Final answer:

H2PO4- will be the major phosphate species present after the addition of 40.0 ml of NaOH in the titration of 0.100 M phosphoric acid.

Step-by-step explanation:

When 40.0 ml of 0.100 M phosphoric acid (H3PO4) is titrated with 0.100 M NaOH, the major phosphate species present after the addition of 40.0 ml of NaOH will be H2PO4-. Phosphoric acid is a polyprotic acid, meaning it can donate multiple protons. The first equivalence point in the titration occurs when all the H3PO4 is converted to H2PO4-, and the pH at this point is approximately 4.6.

User James Brooks
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