Answer:
- 1881.19 feet
- 0.0524 miles or 276.7131 feet
Explanation:
You want the distance to a 500 ft monument given an angle of elevation of 13° to its top and -2° to its bottom. You also want the height of a building if the angle of elevation from 1 mile distant is 3°.
1. Monument
The ratio of opposite side to adjacent side in a right triangle is the tangent of the angle:
Tan = Opposite/Adjacent
If we let the distance to the monument be represented by 'd', then the distance to the ground from the observation height is ...
tan(2°) = (distance to ground)/d
Similarly, the distance to the top from the observation height is ...
tan(13°) = (distance to top)/d
The sum of the distance to the ground and the distance to the top is the height of the monument:
d·tan(2°) +d·tan(13°) = monument height = 500 ft
Then the distance to the monument is ...
d = (500 ft)/(tan(2°) +tan(13°)) ≈ 1881.19 ft . . . distance to the monument
2. Building
The ratio of the building height to the distance from the observation point is the tangent of the angle, as above.
tan(3°) = height/(1 mile)
height = (1 mile)·tan(3°) = 0.0524 mile
There are 5280 feet in a mile, so this is ...
0.0524 mi = (5280 ft)(0.0524) = 276.7131 ft
__
Additional comment
The best angle measurement has an accuracy of perhaps 30 microradians, an arc length of about 2 inches at 1 mile. Reporting the building height to the nearest 0.0001 foot, or 0.0012 inches is a claim of more accuracy than is likely in the measurement of the building height. 0.0001 miles is about 6 inches, so a 4 dp value in miles is reasonably justified.