Question

the weight of chocolate bars from a particular chocolate factory has a mean of 8 ounces with standard deviation of .1 ounce. what is the z-score corresponding to a weight of 8.17 ounces?

Answer 1

The z-score corresponding to a weight of 8.17 ounces of the chocolate bar, with a mean weight of 8 ounces and a standard deviation of .1 ounce, is 1.7. This means the bar is 1.7 standard deviations above the mean weight.

Step-by-step explanation:

The weight of chocolate bars from a particular chocolate factory has a mean of 8 ounces with a standard deviation of .1 ounce. To find the z-score for a chocolate bar that weighs 8.17 ounces, you can use the z-score formula:

Z = (X - μ) / σ

Where,

• X is the value of the data point (8.17 ounces)
• μ is the mean (8 ounces)
• σ is the standard deviation (.1 ounce)

Substituting the given values, we get:

Z = (8.17 - 8) / 0.1 = 0.17 / 0.1 = 1.7

Therefore, the z-score corresponding to a weight of 8.17 ounces is 1.7, which indicates that the weight of the chocolate bar is 1.7 standard deviations above the mean weight.

Answer 2

The z-score corresponding to a weight of 8.17 ounces is 1.7.

Step-by-step explanation:

A Z-score is a statistical measure that quantifies a data point's relation to the mean of a group of data. It is expressed in terms of standard deviations from the mean and helps assess how far a particular value deviates from the average within a dataset.

To find the z-score corresponding to a weight of 8.17 ounces, we can use the formula:

z = (x - μ) / σ

where x is the weight, μ is the mean, and σ is the standard deviation.

Plugging in the values:

z = (8.17 - 8) / 0.1 = 1.7

So, the z-score corresponding to a weight of 8.17 ounces is 1.7.