Question

The volume of a gas is 325 mL when the temperature is 57°C. If the temperature is reduced to 10°C without changing the pressure, what is the new volume of the gas? Combined gas law 2 P₁V₁ T₁ P₂V2 T2 = 278.7 mL​

Answer 1

The new volume of the gas is 278.7 mL.

Step-by-step explanation:

To solve this problem, we can use the combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

where P is the pressure, V is the volume, and T is the temperature.

We can start by plugging in the given values for the initial state of the gas:

P₁ is not given, so we can assume it remains constant.

V₁ = 325 mL

T₁ = 57°C + 273.15 = 330.15 K

Now we can solve for P₂V₂/T₂:

P₂V₂/T₂ = P₁V₁/T₁

We want to solve for V₂, so we can rearrange the equation:

V₂ = (P₁V₁/T₁) * T₂/P₂

We are given that the pressure remains constant, so P₁ = P₂.

Now we can plug in the remaining values:

V₂ = (P₁V₁/T₁) * T₂/P₂

V₂ = (P₁ * 325 mL / 330.15 K) * (10°C + 273.15) / P₁

V₂ = 278.7 mL

Therefore, the new volume of the gas is 278.7 mL.

Hope I helped you!