Question

Pls answer fast !! ASAP
​

Answer 1

Length of Chord which is at the distance of 4 cm from the centre of a circle is 6 cm.

AB = 6 cm.

AC = 6/2 = 3 cm

Distance from the centre = OC = 4 cm.

We are given to find Diameter of the circle.

OA is the radius of the circle. So, firstly we will find the Radius (OA) of the circle.

`\sf AC^2+ OC^2= OA^2 \\ \\ \sf 3^2 + 4^2 = OA^2 \\ \\ \sf9 + 16 = OA^2 \\ \\ \sf 25 = OA^2 \\ \\ \sf OA = \sqrt {25 } \\ \\ \sf OA = 5 cm \\`

Radius of circle (OA) = 5 cm

Diameter = 2 × radius

= 2 × 5

= 10 cm

Therefore, Required diameter of the circle is 10 cm