The answer is 142.
The formula used for the nth term of an arithmetic sequence to solve this problem:
a_n = a_1 + (n - 1)d
where a_n is the nth term of the sequence, a_1 is the first term of the sequence, d is the common difference, and n is the number of the term we want to find.
We are given that d = 4 and a_3 = 10. Plugging these values into the formula, we get:
a_3 = a_1 + (3 - 1)4
10 = a_1 + 8
a_1 = 2
Now we can find the 36th term by plugging in n = 36 and the values we have found for a_1 and d:
a_36 = 2 + (36 - 1)4
a_36 = 2 + 140
a_36 = 142
Therefore, the 36th term of the arithmetic sequence is 142.