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Trucks begin removing gravel from two different piles at the same time. Pile A holds 255 tons of gravel initially, and the gravel is removed at a rate of 20 tons per hour. Pile B holds 220 tons of gravel initially, and the gravel is removed at a rate of 15 tons per hour. After a certain number of hours, the amount of gravel remaining in Pile A equals the amount of gravel remaining in Pile B. At that time, how many tons of gravel will remain in each pile? 70 tons 105 tons 115 tons 140 tons

2 Answers

7 votes

Answer:

115 tons for both piles.

Explanation:

Let's use "h" to represent the number of hours it takes for both piles to have the same amount of gravel remaining.

The amount of gravel remaining in Pile A after "h" hours can be represented as:

255 - 20h

Similarly, the amount of gravel remaining in Pile B after "h" hours can be represented as:

220 - 15h

We know that at this point, the amount of gravel remaining in Pile A will equal the amount of gravel remaining in Pile B, so we can set the two expressions equal to each other and solve for "h":

255 - 20h = 220 - 15h

35 = 5h

h = 7

After 7 hours, Pile A will have:

255 - 20(7) = 115 tons of gravel remaining

After 7 hours, Pile B will have:

220 - 15(7) = 115 tons of gravel remaining

Therefore, the answer is 115 tons for both piles.

User Abhinav Dhiman
by
7.8k points
7 votes

Answer: after 7 hours, there will be 115 tons of gravel remaining in both Pile A and Pile B.

Explanation:

Let t be the number of hours since both trucks began removing gravel. The amount of gravel remaining in Pile A after t hours can be represented by the function:

A(t) = 255 - 20t

Similarly, the amount of gravel remaining in Pile B after t hours can be represented by the function:

B(t) = 220 - 15t

To find the time at which the amount of gravel remaining in both piles is equal, we can set the two functions equal to each other and solve for t:

255 - 20t = 220 - 15t

35 = 5t

t = 7

After 7 hours, the amount of gravel remaining in both piles will be equal. To find the amount of gravel remaining in each pile at that time, we can plug in t = 7 into the two functions:

A(7) = 255 - 20(7) = 115

B(7) = 220 - 15(7) = 115

User Danielgatis
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8.5k points