Question

What is the solute potential (ΨS ) of a 3.0 M NaCL solution at 27°C under standard atmospheric conditions?

Answer 1

The solute potential (ΨS) of a 3.0 M NaCl solution at 27°C under standard atmospheric conditions can be determined using the formula: ΨS = -iCRT. Plugging in the values, the solute potential is calculated to be -147.66 atm.

Step-by-step explanation:

The solute potential (ΨS) of a 3.0 M NaCl solution at 27°C under standard atmospheric conditions can be determined using the formula:

ΨS = -iCRT

Where:

• i is the ionization constant, which is 2 for NaCl because it produces 2 solute particles (Na+ and Cl-) in solution
• C is the molar concentration of the solution in mol/L, which is 3.0 M
• R is the gas constant, which is 0.0821 (L·atm)/(K·mol)
• T is the temperature in Kelvin, which is 27 + 273 = 300 K

Plugging in the values, we have:

ΨS = -(2)(3.0 M)(0.0821 (L·atm)/(K·mol))(300 K)

ΨS = -147.66 atm

Therefore, the solute potential of the 3.0 M NaCl solution at 27°C under standard atmospheric conditions is -147.66 atm.

Answer 2

149.58 bars

Step-by-step explanation:

The solute potential (ΨS) of a solution is given by:

ΨS = iCRT

Where i = ionization constant of the solution, C = molar concentration of the solution, R = pressure constant =0.0831 liter bars/mole-K, and T = temperature in Kelvin.

NaCl dissociates in water to give Na and Cl ions, hence, i = 2

T = 27 + 273 = 300 Kelvin

C = 3.0 M

ΨS = 2 x 3 x 0.0831 x 300

= 149.58 bars.