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How many representatives particles are in 550.0 of palladium(IV) oxide, PdO2?

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ANSWER -

To determine the number of representative particles (atoms, molecules, or formula units) in 550.0 g of palladium(IV) oxide, PdO2, we need to first calculate the number of moles of PdO2, and then use Avogadro's number to convert to representative particles.

The molar mass of PdO2 is the sum of the atomic masses of one palladium atom and two oxygen atoms:

Molar mass of PdO2 = (1 × atomic mass of Pd) + (2 × atomic mass of O)
Molar mass of PdO2 = (1 × 106.42 g/mol) + (2 × 15.999 g/mol)
Molar mass of PdO2 = 148.42 g/mol

We can use this molar mass to convert the mass of PdO2 to moles:

moles of PdO2 = mass of PdO2 / molar mass of PdO2
moles of PdO2 = 550.0 g / 148.42 g/mol
moles of PdO2 = 3.703 mol

Finally, we can use Avogadro's number to convert the number of moles of PdO2 to representative particles:

number of representative particles = moles of PdO2 × Avogadro's number
number of representative particles = 3.703 mol × 6.022 × 10^23 mol^-1
number of representative particles = 2.228 × 10^24

Therefore, there are approximately 2.228 × 10^24 representative particles in 550.0 g of palladium(IV) oxide, PdO2
User Pavel Bakshy
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