ANSWER -
To determine the number of atoms in 0.750 mol of Na3PO4, we need to first calculate the total number of formula units (molecules or ions) in 0.750 mol of Na3PO4, and then multiply by the number of atoms in each formula unit.
One formula unit of Na3PO4 contains 3 sodium atoms (Na), 1 phosphorus atom (P), and 4 oxygen atoms (O). Therefore, the total number of atoms in one formula unit of Na3PO4 is:
3 Na + 1 P + 4 O = 8 atoms
Next, we can use Avogadro's number to convert the number of moles of Na3PO4 to formula units:
number of formula units = moles of Na3PO4 × Avogadro's number
number of formula units = 0.750 mol × 6.022 × 10^23 mol^-1
number of formula units = 4.5165 × 10^23
Finally, we can multiply the number of formula units by the number of atoms in each formula unit to get the total number of atoms:
total number of atoms = number of formula units × number of atoms per formula unit
total number of atoms = 4.5165 × 10^23 × 8
total number of atoms = 3.6132 × 10^24
Therefore, there are approximately 3.6132 × 10^24 atoms in 0.750 mol of Na3PO4