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A cylinder has a radius of 5 cm and a height of 12 cm. What would the height of a cone need to be if it has the same volume and radius?

User Hasumedic
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Answer:

The height of the cone would need to be approximately 2.29 cm if it has the same volume and radius as the given cylinder.

Explanation:

The formula for the volume of a cylinder is V = πr^2h, where r is the radius of the cylinder and h is its height.

For this cylinder, the volume is:

V_cylinder = π(5 cm)^2(12 cm) = 300π cm^3

The formula for the volume of a cone is V = (1/3)πr^2h, where r is the radius of the cone and h is its height.

For a cone with the same radius as the cylinder, the volume would also be 300π cm^3. Therefore, we can set the volume formulas of the cylinder and the cone equal to each other and solve for h:

V_cylinder = V_cone

π(5 cm)^2(12 cm) = (1/3)π(5 cm)^2h

Simplifying this equation, we get:

60 cm^3 = (1/3)(25π)h

180 = 25πh

h = 180 / (25π)

h ≈ 2.29 cm (rounded to two decimal places)

Therefore, the height of the cone would need to be approximately 2.29 cm if it has the same volume and radius as the given cylinder.

User Intrepidhero
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