92.0k views
3 votes
The function f is defined for all x in the closed interval [a,b]. If f does not attain a maximum value on [a,b], which of the following must be true?

answer choices
O f is not continuous on [a,b].

O f is not bounded on [a,b].

O f does not attain a minimum value on [a,b].

O The graph of f has a vertical asymptote in the interval [a,b].

O The equation f'(x) = 0 does not have a solution in the interval [a,b].

2 Answers

2 votes

Final answer:

The function f does not attain a maximum value on [a,b], indicating that it may be unbounded within that interval, which aligns with the Extreme Value Theorem that requires bounded, continuous functions to have maximum and minimum values on a closed interval.

Step-by-step explanation:

If the function f is defined for all x in the closed interval [a,b] and does not attain a maximum value on [a,b], then one possibility is that f is not bounded on [a,b]. By the Extreme Value Theorem, if a function is continuous on a closed interval, it must attain both a maximum and minimum value on that interval. Thus, if f does not attain a maximum value, it might either be discontinuous or not bounded within the interval. However, the only option that deals directly with the boundness is f is not bounded on [a,b]. The existence of vertical asymptotes, non-existence of critical points, or not attaining a minimum value are not necessarily implicated by the fact that f does not have a maximum on the interval.

User Szilard Muzsi
by
8.8k points
5 votes

Final answer:

The correct option is b.

If a function f on a closed interval [a,b] does not attain a maximum value, it implies that f is not bounded on [a,b], due to the Extreme Value Theorem.

Step-by-step explanation:

If a function f defined on a closed interval [a,b] does not attain a maximum value, one possibility that must be true is that f is not bounded on [a,b]. This is due to the Extreme Value Theorem, which states that a continuous function on a closed interval must attain a maximum and minimum value. If f does not attain a maximum, it violates this theorem, suggesting that the function is unbounded.

However, it does not necessarily mean that f is not continuous, has a vertical asymptote, does not attain a minimum value, or that the equation f'(x) = 0 does not have a solution in the interval. Those possibilities can occur under different circumstances or assumptions for function f.

User Toufiq
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories