Question

Need help with this math

Answer 1

average rate of change = - 1

Explanation:

the average rate of change of f(x) in the closed interval [ a, b ] is

`(f(b)-f(a))/(b-a)`

here [ a, b ] = [ - 1, 9 ]

f(b) = f(9) = 9² - 9(9) + 16 = 81 - 81 + 16 = 16

f(a) = f(-1) = (- 1)² - 9(- 1) + 16 = 1 +9 + 16 = 26

then

average rate of change =
`(16-26)/(9-(-1))` =
`(-10)/(9+1)` =
`(-10)/(10)` = - 1