Question

Complete the equation of the line that passes through (-2,6) and (-1,18) in slope intercept form​

Answer 1

`(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{18}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{18}-\stackrel{y1}{6}}}{\underset{\textit{\large run}} {\underset{x_2}{-1}-\underset{x_1}{(-2)}}} \implies \cfrac{12}{-1 +2} \implies \cfrac{ 12 }{ 1 } \implies 12`

`\begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{ 12}(x-\stackrel{x_1}{(-2)}) \implies y -6 = 12 ( x +2) \\\\\\ y-6=12x+24\implies {\Large \begin{array}{llll} y=12x+30 \end{array}}`